Base | Representation |
---|---|
bin | 101101101111110110000110… |
… | …101001100011011011110111 |
3 | 222101101112101002010211222211 |
4 | 231233312012221203123313 |
5 | 202332430101004133421 |
6 | 1551530001021234251 |
7 | 60244135420226152 |
oct | 5557660651433367 |
9 | 871345332124884 |
10 | 201200002021111 |
11 | 5912149495a985 |
12 | 1a695aa9702987 |
13 | 88361041037c2 |
14 | 37981bc516c99 |
15 | 183da190289e1 |
hex | b6fd86a636f7 |
201200002021111 has 2 divisors, whose sum is σ = 201200002021112. Its totient is φ = 201200002021110.
The previous prime is 201200002021093. The next prime is 201200002021127. The reversal of 201200002021111 is 111120200002102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201200002021111 - 217 = 201200001890039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201200002021091 and 201200002021100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201200002021141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100600001010555 + 100600001010556.
It is an arithmetic number, because the mean of its divisors is an integer number (100600001010556).
Almost surely, 2201200002021111 is an apocalyptic number.
201200002021111 is a deficient number, since it is larger than the sum of its proper divisors (1).
201200002021111 is an equidigital number, since it uses as much as digits as its factorization.
201200002021111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 201200002021111 its reverse (111120200002102), we get a palindrome (312320202023213).
The spelling of 201200002021111 in words is "two hundred one trillion, two hundred billion, two million, twenty-one thousand, one hundred eleven".
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