Base | Representation |
---|---|
bin | 11101010001110100100… |
… | …011010100101001100011 |
3 | 21010100022202011122212011 |
4 | 131101310203110221203 |
5 | 230431034012024303 |
6 | 4140144453013351 |
7 | 265235144524015 |
oct | 35216443245143 |
9 | 7110282148764 |
10 | 2012000111203 |
11 | 706314678a65 |
12 | 285b32924257 |
13 | 1179667376a4 |
14 | 6d54a4da1b5 |
15 | 3750b77116d |
hex | 1d4748d4a63 |
2012000111203 has 2 divisors, whose sum is σ = 2012000111204. Its totient is φ = 2012000111202.
The previous prime is 2012000111201. The next prime is 2012000111221. The reversal of 2012000111203 is 3021110002102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2012000111203 - 21 = 2012000111201 is a prime.
It is a super-2 number, since 2×20120001112032 (a number of 25 digits) contains 22 as substring.
Together with 2012000111201, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (2012000111201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006000055601 + 1006000055602.
It is an arithmetic number, because the mean of its divisors is an integer number (1006000055602).
Almost surely, 22012000111203 is an apocalyptic number.
2012000111203 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012000111203 is an equidigital number, since it uses as much as digits as its factorization.
2012000111203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 2012000111203 its reverse (3021110002102), we get a palindrome (5033110113305).
The spelling of 2012000111203 in words is "two trillion, twelve billion, one hundred eleven thousand, two hundred three".
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