Base | Representation |
---|---|
bin | 1001001001100100011011… |
… | …00101000010111001101011 |
3 | 2122020110020112121110211022 |
4 | 10210302031211002321223 |
5 | 10114121231020110011 |
6 | 110443000143523055 |
7 | 4144423260115004 |
oct | 444621545027153 |
9 | 78213215543738 |
10 | 20120002113131 |
11 | 6457932735848 |
12 | 230b483bb948b |
13 | b2c400a5ab7b |
14 | 4d7b559941ab |
15 | 24d57a1078db |
hex | 124c8d942e6b |
20120002113131 has 2 divisors, whose sum is σ = 20120002113132. Its totient is φ = 20120002113130.
The previous prime is 20120002113091. The next prime is 20120002113181. The reversal of 20120002113131 is 13131120002102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20120002113131 - 218 = 20120001850987 is a prime.
It is a super-2 number, since 2×201200021131312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20120002113181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060001056565 + 10060001056566.
It is an arithmetic number, because the mean of its divisors is an integer number (10060001056566).
Almost surely, 220120002113131 is an apocalyptic number.
20120002113131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20120002113131 is an equidigital number, since it uses as much as digits as its factorization.
20120002113131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 20120002113131 its reverse (13131120002102), we get a palindrome (33251122115233).
The spelling of 20120002113131 in words is "twenty trillion, one hundred twenty billion, two million, one hundred thirteen thousand, one hundred thirty-one".
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