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2012001222113 is a prime number
BaseRepresentation
bin11101010001110100100…
…111100011110111100001
321010100022211021002201222
4131101310213203313201
5230431034303101423
64140144532504425
7265235160131561
oct35216447436741
97110284232658
102012001222113
11706315267673
12285b3317b115
13117966a3622c
146d54a708da1
153750b8e03c8
hex1d4749e3de1

2012001222113 has 2 divisors, whose sum is σ = 2012001222114. Its totient is φ = 2012001222112.

The previous prime is 2012001222109. The next prime is 2012001222157. The reversal of 2012001222113 is 3112221002102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1189774829824 + 822226392289 = 1090768^2 + 906767^2 .

It is a cyclic number.

It is not a de Polignac number, because 2012001222113 - 22 = 2012001222109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2012001222091 and 2012001222100.

It is not a weakly prime, because it can be changed into another prime (2012001222103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006000611056 + 1006000611057.

It is an arithmetic number, because the mean of its divisors is an integer number (1006000611057).

Almost surely, 22012001222113 is an apocalyptic number.

It is an amenable number.

2012001222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012001222113 is an equidigital number, since it uses as much as digits as its factorization.

2012001222113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 2012001222113 its reverse (3112221002102), we get a palindrome (5124222224215).

The spelling of 2012001222113 in words is "two trillion, twelve billion, one million, two hundred twenty-two thousand, one hundred thirteen".