Base | Representation |
---|---|
bin | 11101010001110100100… |
… | …111100011110111100001 |
3 | 21010100022211021002201222 |
4 | 131101310213203313201 |
5 | 230431034303101423 |
6 | 4140144532504425 |
7 | 265235160131561 |
oct | 35216447436741 |
9 | 7110284232658 |
10 | 2012001222113 |
11 | 706315267673 |
12 | 285b3317b115 |
13 | 117966a3622c |
14 | 6d54a708da1 |
15 | 3750b8e03c8 |
hex | 1d4749e3de1 |
2012001222113 has 2 divisors, whose sum is σ = 2012001222114. Its totient is φ = 2012001222112.
The previous prime is 2012001222109. The next prime is 2012001222157. The reversal of 2012001222113 is 3112221002102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1189774829824 + 822226392289 = 1090768^2 + 906767^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012001222113 - 22 = 2012001222109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2012001222091 and 2012001222100.
It is not a weakly prime, because it can be changed into another prime (2012001222103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006000611056 + 1006000611057.
It is an arithmetic number, because the mean of its divisors is an integer number (1006000611057).
Almost surely, 22012001222113 is an apocalyptic number.
It is an amenable number.
2012001222113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012001222113 is an equidigital number, since it uses as much as digits as its factorization.
2012001222113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2012001222113 its reverse (3112221002102), we get a palindrome (5124222224215).
The spelling of 2012001222113 in words is "two trillion, twelve billion, one million, two hundred twenty-two thousand, one hundred thirteen".
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