Base | Representation |
---|---|
bin | 11101010001110100101… |
… | …011010101010110000011 |
3 | 21010100022220010100111221 |
4 | 131101310223111112003 |
5 | 230431040031224303 |
6 | 4140145010015511 |
7 | 265235201421325 |
oct | 35216453252603 |
9 | 7110286110457 |
10 | 2012002211203 |
11 | 7063158827a6 |
12 | 285b33577597 |
13 | 117966cc14aa |
14 | 6d54a8c5615 |
15 | 3750ba384bd |
hex | 1d474ad5583 |
2012002211203 has 2 divisors, whose sum is σ = 2012002211204. Its totient is φ = 2012002211202.
The previous prime is 2012002211201. The next prime is 2012002211231. The reversal of 2012002211203 is 3021122002102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2012002211203 - 21 = 2012002211201 is a prime.
It is a super-2 number, since 2×20120022112032 (a number of 25 digits) contains 22 as substring.
Together with 2012002211201, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (2012002211201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006001105601 + 1006001105602.
It is an arithmetic number, because the mean of its divisors is an integer number (1006001105602).
Almost surely, 22012002211203 is an apocalyptic number.
2012002211203 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012002211203 is an equidigital number, since it uses as much as digits as its factorization.
2012002211203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 2012002211203 its reverse (3021122002102), we get a palindrome (5033124213305).
The spelling of 2012002211203 in words is "two trillion, twelve billion, two million, two hundred eleven thousand, two hundred three".
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