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2012010102011 = 7133130828409
BaseRepresentation
bin11101010001110101001…
…001011011110011111011
321010100100102222020200002
4131101311021123303323
5230431044041231021
64140145451103215
7265235325454520
oct35216511336373
97110312866602
102012010102011
1170631a282228
12285b36141b0b
13117968825000
146d54b97b147
153750c59650b
hex1d47525bcfb

2012010102011 has 16 divisors (see below), whose sum is σ = 2490972926400. Its totient is φ = 1591920068544.

The previous prime is 2012010102007. The next prime is 2012010102131. The reversal of 2012010102011 is 1102010102102.

It is not a de Polignac number, because 2012010102011 - 22 = 2012010102007 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2012010101983 and 2012010102001.

It is not an unprimeable number, because it can be changed into a prime (2012010102911) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 65398826 + ... + 65429583.

It is an arithmetic number, because the mean of its divisors is an integer number (155685807900).

Almost surely, 22012010102011 is an apocalyptic number.

2012010102011 is a deficient number, since it is larger than the sum of its proper divisors (478962824389).

2012010102011 is an equidigital number, since it uses as much as digits as its factorization.

2012010102011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 130828455 (or 130828429 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 2012010102011 its reverse (1102010102102), we get a palindrome (3114020204113).

Subtracting from 2012010102011 its reverse (1102010102102), we obtain a palindrome (909999999909).

The spelling of 2012010102011 in words is "two trillion, twelve billion, ten million, one hundred two thousand, eleven".

Divisors: 1 7 13 91 169 1183 2197 15379 130828409 915798863 1700769317 11905385219 22110001121 154770007847 287430014573 2012010102011