Base | Representation |
---|---|
bin | 1011101101100010000… |
… | …1010111001111111011 |
3 | 201020100001101220201122 |
4 | 2323120201113033323 |
5 | 11244024441322001 |
6 | 232232554135455 |
7 | 20351644206215 |
oct | 2733041271773 |
9 | 636301356648 |
10 | 201201120251 |
11 | 7836887266a |
12 | 32bb1a2158b |
13 | 15c86116511 |
14 | 9a498235b5 |
15 | 5378b31b1b |
hex | 2ed88573fb |
201201120251 has 2 divisors, whose sum is σ = 201201120252. Its totient is φ = 201201120250.
The previous prime is 201201120173. The next prime is 201201120257. The reversal of 201201120251 is 152021102102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201201120251 is a prime.
It is not a weakly prime, because it can be changed into another prime (201201120257) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100600560125 + 100600560126.
It is an arithmetic number, because the mean of its divisors is an integer number (100600560126).
Almost surely, 2201201120251 is an apocalyptic number.
201201120251 is a deficient number, since it is larger than the sum of its proper divisors (1).
201201120251 is an equidigital number, since it uses as much as digits as its factorization.
201201120251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 201201120251 its reverse (152021102102), we get a palindrome (353222222353).
The spelling of 201201120251 in words is "two hundred one billion, two hundred one million, one hundred twenty thousand, two hundred fifty-one".
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