Search a number
-
+
201201132013 = 728743018859
BaseRepresentation
bin1011101101100010000…
…1011010000111101101
3201020100001102111212021
42323120201122013231
511244024442211023
6232232554310141
720351644255420
oct2733041320755
9636301374767
10201201132013
1178368880492
1232bb1a28351
1315c8611b98b
149a498279b7
155378b3535d
hex2ed885a1ed

201201132013 has 4 divisors (see below), whose sum is σ = 229944150880. Its totient is φ = 172458113148.

The previous prime is 201201131987. The next prime is 201201132103. The reversal of 201201132013 is 310231102102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201201132013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201201136013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14371509423 + ... + 14371509436.

It is an arithmetic number, because the mean of its divisors is an integer number (57486037720).

Almost surely, 2201201132013 is an apocalyptic number.

It is an amenable number.

201201132013 is a deficient number, since it is larger than the sum of its proper divisors (28743018867).

201201132013 is an equidigital number, since it uses as much as digits as its factorization.

201201132013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28743018866.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 201201132013 its reverse (310231102102), we get a palindrome (511432234115).

The spelling of 201201132013 in words is "two hundred one billion, two hundred one million, one hundred thirty-two thousand, thirteen".

Divisors: 1 7 28743018859 201201132013