Base | Representation |
---|---|
bin | 11101010001110111000… |
… | …011101010111100000111 |
3 | 21010100102200021020010120 |
4 | 131101313003222330013 |
5 | 230431130242124133 |
6 | 4140152553553023 |
7 | 265236165024063 |
oct | 35216703527407 |
9 | 7110380236116 |
10 | 2012042145543 |
11 | 706336378a91 |
12 | 285b44a15773 |
13 | 117972364191 |
14 | 6d551d1caa3 |
15 | 375102c5ab3 |
hex | 1d4770eaf07 |
2012042145543 has 4 divisors (see below), whose sum is σ = 2682722860728. Its totient is φ = 1341361430360.
The previous prime is 2012042145527. The next prime is 2012042145583. The reversal of 2012042145543 is 3455412402102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2012042145543 - 24 = 2012042145527 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2012042145583) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335340357588 + ... + 335340357593.
It is an arithmetic number, because the mean of its divisors is an integer number (670680715182).
Almost surely, 22012042145543 is an apocalyptic number.
2012042145543 is a deficient number, since it is larger than the sum of its proper divisors (670680715185).
2012042145543 is an equidigital number, since it uses as much as digits as its factorization.
2012042145543 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 670680715184.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 2012042145543 its reverse (3455412402102), we get a palindrome (5467454547645).
The spelling of 2012042145543 in words is "two trillion, twelve billion, forty-two million, one hundred forty-five thousand, five hundred forty-three".
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