Base | Representation |
---|---|
bin | 101101110000000000010111… |
… | …011100011001001100010101 |
3 | 222101102120211000200020201211 |
4 | 231300000113130121030111 |
5 | 202333120132411432242 |
6 | 1551535022252421421 |
7 | 60245005451560426 |
oct | 5560002734311425 |
9 | 871376730606654 |
10 | 201211021202197 |
11 | 591261299a9806 |
12 | 1a698063a77871 |
13 | 883716bcb58b6 |
14 | 3798945b7b64d |
15 | 183de61606317 |
hex | b70017719315 |
201211021202197 has 2 divisors, whose sum is σ = 201211021202198. Its totient is φ = 201211021202196.
The previous prime is 201211021202189. The next prime is 201211021202299. The reversal of 201211021202197 is 791202120112102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111579377376996 + 89631643825201 = 10563114^2 + 9467399^2 .
It is a cyclic number.
It is not a de Polignac number, because 201211021202197 - 23 = 201211021202189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201211021202117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100605510601098 + 100605510601099.
It is an arithmetic number, because the mean of its divisors is an integer number (100605510601099).
Almost surely, 2201211021202197 is an apocalyptic number.
It is an amenable number.
201211021202197 is a deficient number, since it is larger than the sum of its proper divisors (1).
201211021202197 is an equidigital number, since it uses as much as digits as its factorization.
201211021202197 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 31.
Adding to 201211021202197 its reverse (791202120112102), we get a palindrome (992413141314299).
The spelling of 201211021202197 in words is "two hundred one trillion, two hundred eleven billion, twenty-one million, two hundred two thousand, one hundred ninety-seven".
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