Base | Representation |
---|---|
bin | 11101010001111011000… |
… | …111101111110110111011 |
3 | 21010100121102120000012102 |
4 | 131101323013233312323 |
5 | 230431300220320011 |
6 | 4140203431134015 |
7 | 265240653360416 |
oct | 35217307576673 |
9 | 7110542500172 |
10 | 2012110323131 |
11 | 7063709048a7 |
12 | 285b6381430b |
13 | 11798351534c |
14 | 6d55adc8b7d |
15 | 3751629173b |
hex | 1d47b1efdbb |
2012110323131 has 2 divisors, whose sum is σ = 2012110323132. Its totient is φ = 2012110323130.
The previous prime is 2012110323101. The next prime is 2012110323161. The reversal of 2012110323131 is 1313230112102.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (2012110323101) and next prime (2012110323161).
It is a cyclic number.
It is not a de Polignac number, because 2012110323131 - 210 = 2012110322107 is a prime.
It is a super-2 number, since 2×20121103231312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2012110323101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006055161565 + 1006055161566.
It is an arithmetic number, because the mean of its divisors is an integer number (1006055161566).
Almost surely, 22012110323131 is an apocalyptic number.
2012110323131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012110323131 is an equidigital number, since it uses as much as digits as its factorization.
2012110323131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 2012110323131 its reverse (1313230112102), we get a palindrome (3325340435233).
The spelling of 2012110323131 in words is "two trillion, twelve billion, one hundred ten million, three hundred twenty-three thousand, one hundred thirty-one".
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