Base | Representation |
---|---|
bin | 11101010001111011001… |
… | …011001000101011000001 |
3 | 21010100121111020010101220 |
4 | 131101323023020223001 |
5 | 230431300432224301 |
6 | 4140203502145253 |
7 | 265240664046510 |
oct | 35217313105301 |
9 | 7110544203356 |
10 | 2012111211201 |
11 | 706371361043 |
12 | 285b63b82229 |
13 | 117983766630 |
14 | 6d55b17a677 |
15 | 375163b9936 |
hex | 1d47b2c8ac1 |
2012111211201 has 64 divisors (see below), whose sum is σ = 3318841344000. Its totient is φ = 1055900240640.
The previous prime is 2012111211199. The next prime is 2012111211251. The reversal of 2012111211201 is 1021121112102.
It is a happy number.
It is not a de Polignac number, because 2012111211201 - 21 = 2012111211199 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2012111211251) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 206386675 + ... + 206396423.
It is an arithmetic number, because the mean of its divisors is an integer number (51856896000).
Almost surely, 22012111211201 is an apocalyptic number.
2012111211201 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
2012111211201 is a deficient number, since it is larger than the sum of its proper divisors (1306730132799).
2012111211201 is a wasteful number, since it uses less digits than its factorization.
2012111211201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13566.
The product of its (nonzero) digits is 16, while the sum is 15.
Adding to 2012111211201 its reverse (1021121112102), we get a palindrome (3033232323303).
Subtracting from 2012111211201 its reverse (1021121112102), we obtain a palindrome (990990099099).
The spelling of 2012111211201 in words is "two trillion, twelve billion, one hundred eleven million, two hundred eleven thousand, two hundred one".
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