Base | Representation |
---|---|
bin | 1001001001100110100000… |
… | …10001101011111111000011 |
3 | 2122020120010112012111200222 |
4 | 10210303100101223333003 |
5 | 10114131024001041003 |
6 | 110443303155533255 |
7 | 4144463065340252 |
oct | 444632021537703 |
9 | 78216115174628 |
10 | 20121121112003 |
11 | 64583573471aa |
12 | 230b7368ba22b |
13 | b2c54b831392 |
14 | 4d7c2043a799 |
15 | 24d5e3492c38 |
hex | 124cd046bfc3 |
20121121112003 has 2 divisors, whose sum is σ = 20121121112004. Its totient is φ = 20121121112002.
The previous prime is 20121121111997. The next prime is 20121121112089. The reversal of 20121121112003 is 30021112112102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20121121112003 - 214 = 20121121095619 is a prime.
It is not a weakly prime, because it can be changed into another prime (20121120112003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060560556001 + 10060560556002.
It is an arithmetic number, because the mean of its divisors is an integer number (10060560556002).
Almost surely, 220121121112003 is an apocalyptic number.
20121121112003 is a deficient number, since it is larger than the sum of its proper divisors (1).
20121121112003 is an equidigital number, since it uses as much as digits as its factorization.
20121121112003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 20121121112003 its reverse (30021112112102), we get a palindrome (50142233224105).
The spelling of 20121121112003 in words is "twenty trillion, one hundred twenty-one billion, one hundred twenty-one million, one hundred twelve thousand, three".
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