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201211211130000 = 24354311391556519
BaseRepresentation
bin101101110000000000100010…
…110000111010010010010000
3222101102121022021001120200220
4231300000202300322102100
5202333121030022130000
61551535053155313040
760245013246125001
oct5560004260722220
9871377267046626
10201211211130000
1159126217132335
121a6980b75ab780
13883719c454506
14379896309b1a8
15183de731211a0
hexb70022c3a490

201211211130000 has 400 divisors, whose sum is σ = 675313510502400. Its totient is φ = 51551876160000.

The previous prime is 201211211129963. The next prime is 201211211130043. The reversal of 201211211130000 is 31112112102.

It is a tau number, because it is divible by the number of its divisors (400).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 128491741 + ... + 130048259.

It is an arithmetic number, because the mean of its divisors is an integer number (1688283776256).

Almost surely, 2201211211130000 is an apocalyptic number.

201211211130000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201211211130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (337656755251200).

201211211130000 is an abundant number, since it is smaller than the sum of its proper divisors (474102299372400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201211211130000 is a wasteful number, since it uses less digits than its factorization.

201211211130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1556720 (or 1556699 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 201211211130000 its reverse (31112112102), we get a palindrome (201242323242102).

The spelling of 201211211130000 in words is "two hundred one trillion, two hundred eleven billion, two hundred eleven million, one hundred thirty thousand".