Base | Representation |
---|---|
bin | 1011101101100100100… |
… | …0001111101111101011 |
3 | 201020100202120202201201 |
4 | 2323121020033233223 |
5 | 11244040044010011 |
6 | 232234000425031 |
7 | 20352126641113 |
oct | 2733110175753 |
9 | 636322522651 |
10 | 201211313131 |
11 | 783735a4734 |
12 | 32bb5318177 |
13 | 15c88274aca |
14 | 9a4ad18043 |
15 | 5379996cc1 |
hex | 2ed920fbeb |
201211313131 has 2 divisors, whose sum is σ = 201211313132. Its totient is φ = 201211313130.
The previous prime is 201211313003. The next prime is 201211313161. The reversal of 201211313131 is 131313112102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201211313131 - 27 = 201211313003 is a prime.
It is a super-2 number, since 2×2012113131312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 201211313099 and 201211313108.
It is not a weakly prime, because it can be changed into another prime (201211313161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100605656565 + 100605656566.
It is an arithmetic number, because the mean of its divisors is an integer number (100605656566).
Almost surely, 2201211313131 is an apocalyptic number.
201211313131 is a deficient number, since it is larger than the sum of its proper divisors (1).
201211313131 is an equidigital number, since it uses as much as digits as its factorization.
201211313131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 201211313131 its reverse (131313112102), we get a palindrome (332524425233).
The spelling of 201211313131 in words is "two hundred one billion, two hundred eleven million, three hundred thirteen thousand, one hundred thirty-one".
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