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20121200011313 is a prime number
BaseRepresentation
bin1001001001100110101001…
…11110101010100000110001
32122020120100000200000012122
410210303110332222200301
510114131204200330223
6110443315055004025
74144465044100352
oct444632476524061
978216300600178
1020121200011313
116458397936445
12230b759209615
13b2c561c9776b
144d7c2aad7d29
1524d5ea37a5c8
hex124cd4faa831

20121200011313 has 2 divisors, whose sum is σ = 20121200011314. Its totient is φ = 20121200011312.

The previous prime is 20121200011163. The next prime is 20121200011327. The reversal of 20121200011313 is 31311000212102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15769103087089 + 4352096924224 = 3971033^2 + 2086168^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20121200011313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20121200011291 and 20121200011300.

It is not a weakly prime, because it can be changed into another prime (20121200011513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060600005656 + 10060600005657.

It is an arithmetic number, because the mean of its divisors is an integer number (10060600005657).

Almost surely, 220121200011313 is an apocalyptic number.

It is an amenable number.

20121200011313 is a deficient number, since it is larger than the sum of its proper divisors (1).

20121200011313 is an equidigital number, since it uses as much as digits as its factorization.

20121200011313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 20121200011313 its reverse (31311000212102), we get a palindrome (51432200223415).

The spelling of 20121200011313 in words is "twenty trillion, one hundred twenty-one billion, two hundred million, eleven thousand, three hundred thirteen".