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201212120011100 = 22521129791512292309
BaseRepresentation
bin101101110000000001011000…
…111100000001000101011100
3222101102200122121021112011212
4231300001120330001011130
5202333124410210323400
61551535323304003552
760245044623363062
oct5560013074010534
9871380577245155
10201212120011100
1159126643180140
121a69830ba605b8
1388372b583a393
143798a0ba8a032
15183dec7d04335
hexb70058f0115c

201212120011100 has 576 divisors, whose sum is σ = 504702696960000. Its totient is φ = 68956392960000.

The previous prime is 201212120011087. The next prime is 201212120011117. The reversal of 201212120011100 is 1110021212102.

It is a super-2 number, since 2×2012121200111002 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 87142536746 + ... + 87142539054.

It is an arithmetic number, because the mean of its divisors is an integer number (876219960000).

Almost surely, 2201212120011100 is an apocalyptic number.

201212120011100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201212120011100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (252351348480000).

201212120011100 is an abundant number, since it is smaller than the sum of its proper divisors (303490576948900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201212120011100 is a wasteful number, since it uses less digits than its factorization.

201212120011100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2822 (or 2815 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 201212120011100 its reverse (1110021212102), we get a palindrome (202322141223202).

The spelling of 201212120011100 in words is "two hundred one trillion, two hundred twelve billion, one hundred twenty million, eleven thousand, one hundred".