Base | Representation |
---|---|
bin | 1001001001101000001001… |
… | …01110111111101101000111 |
3 | 2122020122101212021010102212 |
4 | 10210310010232333231013 |
5 | 10114134324302211213 |
6 | 110443530355254035 |
7 | 4144523643136205 |
oct | 444640456775507 |
9 | 78218355233385 |
10 | 20122001210183 |
11 | 6458769115a74 |
12 | 230b9415aa31b |
13 | b2c65bc7a232 |
14 | 4d7ca5296075 |
15 | 24d64588c9a8 |
hex | 124d04bbfb47 |
20122001210183 has 2 divisors, whose sum is σ = 20122001210184. Its totient is φ = 20122001210182.
The previous prime is 20122001210177. The next prime is 20122001210279. The reversal of 20122001210183 is 38101210022102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20122001210183 is a prime.
It is a super-2 number, since 2×201220012101832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20122001210173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061000605091 + 10061000605092.
It is an arithmetic number, because the mean of its divisors is an integer number (10061000605092).
Almost surely, 220122001210183 is an apocalyptic number.
20122001210183 is a deficient number, since it is larger than the sum of its proper divisors (1).
20122001210183 is an equidigital number, since it uses as much as digits as its factorization.
20122001210183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 20122001210183 its reverse (38101210022102), we get a palindrome (58223211232285).
The spelling of 20122001210183 in words is "twenty trillion, one hundred twenty-two billion, one million, two hundred ten thousand, one hundred eighty-three".
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