Base | Representation |
---|---|
bin | 11101010010000000100… |
… | …010011111011110110111 |
3 | 21010100211202121001021222 |
4 | 131102000202133132313 |
5 | 230431442003020043 |
6 | 4140220435300555 |
7 | 265243136110061 |
oct | 35220042373667 |
9 | 7110752531258 |
10 | 2012201220023 |
11 | 706408148aa5 |
12 | 285b8a14a75b |
13 | 1179992bc5a7 |
14 | 6d5690ca731 |
15 | 3751e248d68 |
hex | 1d48089f7b7 |
2012201220023 has 2 divisors, whose sum is σ = 2012201220024. Its totient is φ = 2012201220022.
The previous prime is 2012201219993. The next prime is 2012201220091. The reversal of 2012201220023 is 3200221022102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2012201220023 - 28 = 2012201219767 is a prime.
It is a super-2 number, since 2×20122012200232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2012201219983 and 2012201220010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012201229023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006100610011 + 1006100610012.
It is an arithmetic number, because the mean of its divisors is an integer number (1006100610012).
Almost surely, 22012201220023 is an apocalyptic number.
2012201220023 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012201220023 is an equidigital number, since it uses as much as digits as its factorization.
2012201220023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 17.
Adding to 2012201220023 its reverse (3200221022102), we get a palindrome (5212422242125).
The spelling of 2012201220023 in words is "two trillion, twelve billion, two hundred one million, two hundred twenty thousand, twenty-three".
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