Base | Representation |
---|---|
bin | 11101010010000000100… |
… | …010111010110100100000 |
3 | 21010100211202210201220021 |
4 | 131102000202322310200 |
5 | 230431442020111000 |
6 | 4140220441523224 |
7 | 265243140054406 |
oct | 35220042726440 |
9 | 7110752721807 |
10 | 2012201332000 |
11 | 706408215142 |
12 | 285b8a1a3514 |
13 | 11799932b552 |
14 | 6d569119476 |
15 | 3751e26c11a |
hex | 1d4808bad20 |
2012201332000 has 48 divisors (see below), whose sum is σ = 4943978682552. Its totient is φ = 804880531200.
The previous prime is 2012201331991. The next prime is 2012201332007. The reversal of 2012201332000 is 2331022102.
It can be written as a sum of positive squares in 4 ways, for example, as 459515871376 + 1552685460624 = 677876^2 + 1246068^2 .
It is a Harshad number since it is a multiple of its sum of digits (16).
It is not an unprimeable number, because it can be changed into a prime (2012201332007) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 251521167 + ... + 251529166.
Almost surely, 22012201332000 is an apocalyptic number.
2012201332000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2012201332000 is an abundant number, since it is smaller than the sum of its proper divisors (2931777350552).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2012201332000 is an equidigital number, since it uses as much as digits as its factorization.
2012201332000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 503050358 (or 503050340 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 2012201332000 its reverse (2331022102), we get a palindrome (2014532354102).
The spelling of 2012201332000 in words is "two trillion, twelve billion, two hundred one million, three hundred thirty-two thousand".
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