Base | Representation |
---|---|
bin | 11101010010000001001… |
… | …000111100011111001101 |
3 | 21010100212110120011211121 |
4 | 131102001020330133031 |
5 | 230432002043102201 |
6 | 4140221435320541 |
7 | 265243320562456 |
oct | 35220110743715 |
9 | 7110773504747 |
10 | 2012211300301 |
11 | 706412903504 |
12 | 285b915b0151 |
13 | 11799b40b857 |
14 | 6d56a59212d |
15 | 3752008a9a1 |
hex | 1d48123c7cd |
2012211300301 has 4 divisors (see below), whose sum is σ = 2025537203104. Its totient is φ = 1998885397500.
The previous prime is 2012211300299. The next prime is 2012211300313. The reversal of 2012211300301 is 1030031122102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2012211300301 - 21 = 2012211300299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2012211300371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6662951175 + ... + 6662951476.
It is an arithmetic number, because the mean of its divisors is an integer number (506384300776).
Almost surely, 22012211300301 is an apocalyptic number.
It is an amenable number.
2012211300301 is a deficient number, since it is larger than the sum of its proper divisors (13325902803).
2012211300301 is a wasteful number, since it uses less digits than its factorization.
2012211300301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13325902802.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 2012211300301 its reverse (1030031122102), we get a palindrome (3042242422403).
The spelling of 2012211300301 in words is "two trillion, twelve billion, two hundred eleven million, three hundred thousand, three hundred one".
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