Base | Representation |
---|---|
bin | 1001001001101000100100… |
… | …11100011000110011101111 |
3 | 2122020122222220001111101122 |
4 | 10210310102130120303233 |
5 | 10114140312142311140 |
6 | 110444005253131155 |
7 | 4144532435134211 |
oct | 444642234306357 |
9 | 78218886044348 |
10 | 20122231213295 |
11 | 6458876a30792 |
12 | 230b9a6629abb |
13 | b2c69780aa53 |
14 | 4d7cc7a485b1 |
15 | 24d65ab71ab5 |
hex | 124d12718cef |
20122231213295 has 4 divisors (see below), whose sum is σ = 24146677455960. Its totient is φ = 16097784970632.
The previous prime is 20122231213219. The next prime is 20122231213349. The reversal of 20122231213295 is 59231213222102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20122231213295 - 220 = 20122230164719 is a prime.
It is a super-4 number, since 4×201222312132954 (a number of 54 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2012223121325 + ... + 2012223121334.
It is an arithmetic number, because the mean of its divisors is an integer number (6036669363990).
Almost surely, 220122231213295 is an apocalyptic number.
20122231213295 is a deficient number, since it is larger than the sum of its proper divisors (4024446242665).
20122231213295 is an equidigital number, since it uses as much as digits as its factorization.
20122231213295 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4024446242664.
The product of its (nonzero) digits is 25920, while the sum is 35.
Adding to 20122231213295 its reverse (59231213222102), we get a palindrome (79353444435397).
The spelling of 20122231213295 in words is "twenty trillion, one hundred twenty-two billion, two hundred thirty-one million, two hundred thirteen thousand, two hundred ninety-five".
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