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2012254334203 is a prime number
BaseRepresentation
bin11101010010000011101…
…101000110110011111011
321010100222110112112020211
4131102003231012303323
5230432044102143303
64140230013531551
7265244352424651
oct35220355066373
97110873475224
102012254334203
11706435126513
12285ba3aa3bb7
131179a72c82b9
146d572194dd1
1537523c3b66d
hex1d483b46cfb

2012254334203 has 2 divisors, whose sum is σ = 2012254334204. Its totient is φ = 2012254334202.

The previous prime is 2012254334201. The next prime is 2012254334227. The reversal of 2012254334203 is 3024334522102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2012254334203 - 21 = 2012254334201 is a prime.

Together with 2012254334201, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (2012254334201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006127167101 + 1006127167102.

It is an arithmetic number, because the mean of its divisors is an integer number (1006127167102).

Almost surely, 22012254334203 is an apocalyptic number.

2012254334203 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012254334203 is an equidigital number, since it uses as much as digits as its factorization.

2012254334203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 2012254334203 its reverse (3024334522102), we get a palindrome (5036588856305).

The spelling of 2012254334203 in words is "two trillion, twelve billion, two hundred fifty-four million, three hundred thirty-four thousand, two hundred three".