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20123004013127 is a prime number
BaseRepresentation
bin1001001001101010000001…
…00000011000101001000111
32122020201222202012210110122
410210311000200120221013
510114143403011410002
6110444214101012155
74144560540623021
oct444650040305107
978221882183418
1020123004013127
116459133183734
12230bb813b405b
13b2c78b959162
144d7d5c533011
1524d6a39246a2
hex124d40818a47

20123004013127 has 2 divisors, whose sum is σ = 20123004013128. Its totient is φ = 20123004013126.

The previous prime is 20123004013097. The next prime is 20123004013183. The reversal of 20123004013127 is 72131040032102.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20123004013127 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20123004013096 and 20123004013105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20123004013187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061502006563 + 10061502006564.

It is an arithmetic number, because the mean of its divisors is an integer number (10061502006564).

Almost surely, 220123004013127 is an apocalyptic number.

20123004013127 is a deficient number, since it is larger than the sum of its proper divisors (1).

20123004013127 is an equidigital number, since it uses as much as digits as its factorization.

20123004013127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 20123004013127 its reverse (72131040032102), we get a palindrome (92254044045229).

The spelling of 20123004013127 in words is "twenty trillion, one hundred twenty-three billion, four million, thirteen thousand, one hundred twenty-seven".