20123130000401 has 2 divisors, whose sum is σ = 20123130000402. Its totient is φ = 20123130000400.

The previous prime is 20123130000383. The next prime is 20123130000403. The reversal of 20123130000401 is 10400003132102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17011871457025 + 3111258543376 = 4124545^2 + 1763876^2 .

It is a cyclic number.

It is not a de Polignac number, because 20123130000401 - 2²² = 20123125806097 is a prime.

It is a super-2 number, since 2×20123130000401² (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 20123130000403, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 20123130000401.

It is not a weakly prime, because it can be changed into another prime (20123130000403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061565000200 + 10061565000201.

It is an arithmetic number, because the mean of its divisors is an integer number (10061565000201).

Almost surely, 2^{20123130000401} is an apocalyptic number.

It is an amenable number.

20123130000401 is a deficient number, since it is larger than the sum of its proper divisors (1).

20123130000401 is an equidigital number, since it uses as much as digits as its factorization.

20123130000401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 20123130000401 its reverse (10400003132102), we get a palindrome (30523133132503).

The spelling of 20123130000401 in words is "twenty trillion, one hundred twenty-three billion, one hundred thirty million, four hundred one", and thus it is an aban number.