Base | Representation |
---|---|
bin | 1001001001101010011010… |
… | …11101010100011100011111 |
3 | 2122020202112220002210021121 |
4 | 10210311031131110130133 |
5 | 10114144324124011221 |
6 | 110444251422311411 |
7 | 4144566116633164 |
oct | 444651535243437 |
9 | 78222486083247 |
10 | 20123221313311 |
11 | 6459234902566 |
12 | 2310022128567 |
13 | b2c7c498ca4c |
14 | 4d7d7d33a06b |
15 | 24d6b7a49a41 |
hex | 124d4d75471f |
20123221313311 has 4 divisors (see below), whose sum is σ = 21306940214112. Its totient is φ = 18939502412512.
The previous prime is 20123221313213. The next prime is 20123221313317. The reversal of 20123221313311 is 11331312232102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20123221313311 - 221 = 20123219216159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20123221313317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591859450375 + ... + 591859450408.
It is an arithmetic number, because the mean of its divisors is an integer number (5326735053528).
Almost surely, 220123221313311 is an apocalyptic number.
20123221313311 is a deficient number, since it is larger than the sum of its proper divisors (1183718900801).
20123221313311 is a wasteful number, since it uses less digits than its factorization.
20123221313311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1183718900800.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 20123221313311 its reverse (11331312232102), we get a palindrome (31454533545413).
The spelling of 20123221313311 in words is "twenty trillion, one hundred twenty-three billion, two hundred twenty-one million, three hundred thirteen thousand, three hundred eleven".
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