Base | Representation |
---|---|
bin | 1011101101101011100… |
… | …1101011110100111111 |
3 | 201020102211112120122012 |
4 | 2323122321223310333 |
5 | 11244120202103211 |
6 | 232240542041435 |
7 | 20352640463561 |
oct | 2733271536477 |
9 | 636384476565 |
10 | 201241050431 |
11 | 78389365813 |
12 | 3300327927b |
13 | 15c91487345 |
14 | 9a50c59331 |
15 | 537c3bcd8b |
hex | 2edae6bd3f |
201241050431 has 2 divisors, whose sum is σ = 201241050432. Its totient is φ = 201241050430.
The previous prime is 201241050391. The next prime is 201241050497. The reversal of 201241050431 is 134050142102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201241050431 - 214 = 201241034047 is a prime.
It is a super-2 number, since 2×2012410504312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 201241050397 and 201241050406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201241059431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100620525215 + 100620525216.
It is an arithmetic number, because the mean of its divisors is an integer number (100620525216).
Almost surely, 2201241050431 is an apocalyptic number.
201241050431 is a deficient number, since it is larger than the sum of its proper divisors (1).
201241050431 is an equidigital number, since it uses as much as digits as its factorization.
201241050431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 201241050431 its reverse (134050142102), we get a palindrome (335291192533).
The spelling of 201241050431 in words is "two hundred one billion, two hundred forty-one million, fifty thousand, four hundred thirty-one".
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