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201241050431 is a prime number
BaseRepresentation
bin1011101101101011100…
…1101011110100111111
3201020102211112120122012
42323122321223310333
511244120202103211
6232240542041435
720352640463561
oct2733271536477
9636384476565
10201241050431
1178389365813
123300327927b
1315c91487345
149a50c59331
15537c3bcd8b
hex2edae6bd3f

201241050431 has 2 divisors, whose sum is σ = 201241050432. Its totient is φ = 201241050430.

The previous prime is 201241050391. The next prime is 201241050497. The reversal of 201241050431 is 134050142102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201241050431 - 214 = 201241034047 is a prime.

It is a super-2 number, since 2×2012410504312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201241050397 and 201241050406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201241059431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100620525215 + 100620525216.

It is an arithmetic number, because the mean of its divisors is an integer number (100620525216).

Almost surely, 2201241050431 is an apocalyptic number.

201241050431 is a deficient number, since it is larger than the sum of its proper divisors (1).

201241050431 is an equidigital number, since it uses as much as digits as its factorization.

201241050431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 201241050431 its reverse (134050142102), we get a palindrome (335291192533).

The spelling of 201241050431 in words is "two hundred one billion, two hundred forty-one million, fifty thousand, four hundred thirty-one".