Base | Representation |
---|---|
bin | 10010101111100100… |
… | …011100000011011001 |
3 | 1220221120112222110011 |
4 | 102233210130003121 |
5 | 312204102342243 |
6 | 13125005521521 |
7 | 1311504236623 |
oct | 225744340331 |
9 | 56846488404 |
10 | 20125434073 |
11 | 8598312548 |
12 | 3a97b732a1 |
13 | 1b89685094 |
14 | d8cc17c13 |
15 | 7cbc9689d |
hex | 4af91c0d9 |
20125434073 has 2 divisors, whose sum is σ = 20125434074. Its totient is φ = 20125434072.
The previous prime is 20125434041. The next prime is 20125434113. The reversal of 20125434073 is 37043452102.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13695318729 + 6430115344 = 117027^2 + 80188^2 .
It is a cyclic number.
It is not a de Polignac number, because 20125434073 - 25 = 20125434041 is a prime.
It is not a weakly prime, because it can be changed into another prime (20165434073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10062717036 + 10062717037.
It is an arithmetic number, because the mean of its divisors is an integer number (10062717037).
Almost surely, 220125434073 is an apocalyptic number.
It is an amenable number.
20125434073 is a deficient number, since it is larger than the sum of its proper divisors (1).
20125434073 is an equidigital number, since it uses as much as digits as its factorization.
20125434073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 31.
Adding to 20125434073 its reverse (37043452102), we get a palindrome (57168886175).
The spelling of 20125434073 in words is "twenty billion, one hundred twenty-five million, four hundred thirty-four thousand, seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.870 sec. • engine limits •