Base | Representation |
---|---|
bin | 11101010010010101011… |
… | …101110011010011100011 |
3 | 21010101202020020100222211 |
4 | 131102111131303103203 |
5 | 230433201342441120 |
6 | 4140315340342551 |
7 | 265254631252666 |
oct | 35222535632343 |
9 | 7111666210884 |
10 | 2012552312035 |
11 | 706578349691 |
12 | 286067844a57 |
13 | 117a23c68845 |
14 | 6d59d99d6dd |
15 | 3753ee9b25a |
hex | 1d4957734e3 |
2012552312035 has 8 divisors (see below), whose sum is σ = 2415133253376. Its totient is φ = 1609994863680.
The previous prime is 2012552312021. The next prime is 2012552312101. The reversal of 2012552312035 is 5302132552102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2012552312035 - 223 = 2012543923427 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2012552311988 and 2012552312006.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5684226 + ... + 6027895.
It is an arithmetic number, because the mean of its divisors is an integer number (301891656672).
Almost surely, 22012552312035 is an apocalyptic number.
2012552312035 is a deficient number, since it is larger than the sum of its proper divisors (402580941341).
2012552312035 is a wasteful number, since it uses less digits than its factorization.
2012552312035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11746493.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 2012552312035 its reverse (5302132552102), we get a palindrome (7314684864137).
The spelling of 2012552312035 in words is "two trillion, twelve billion, five hundred fifty-two million, three hundred twelve thousand, thirty-five".
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