Base | Representation |
---|---|
bin | 1011101101111001101… |
… | …1000001101000000000 |
3 | 201020120221200201202020 |
4 | 2323132123001220000 |
5 | 11244230312401422 |
6 | 232250452121440 |
7 | 20354255543325 |
oct | 2733633015000 |
9 | 636527621666 |
10 | 201300122112 |
11 | 78409742191 |
12 | 3301b006280 |
13 | 15ca079a8bb |
14 | 9a58a34b4c |
15 | 538268a95c |
hex | 2ede6c1a00 |
201300122112 has 80 divisors (see below), whose sum is σ = 536483787840. Its totient is φ = 67074056192.
The previous prime is 201300122059. The next prime is 201300122113. The reversal of 201300122112 is 211221003102.
It is a super-2 number, since 2×2013001221122 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 201300122091 and 201300122100.
It is not an unprimeable number, because it can be changed into a prime (201300122113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4167733 + ... + 4215755.
It is an arithmetic number, because the mean of its divisors is an integer number (6706047348).
Almost surely, 2201300122112 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 201300122112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (268241893920).
201300122112 is an abundant number, since it is smaller than the sum of its proper divisors (335183665728).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201300122112 is an equidigital number, since it uses as much as digits as its factorization.
201300122112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50773 (or 50757 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 201300122112 its reverse (211221003102), we get a palindrome (412521125214).
The spelling of 201300122112 in words is "two hundred one billion, three hundred million, one hundred twenty-two thousand, one hundred twelve".
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