2013011102023 has 4 divisors (see below), whose sum is σ = 2013014931928. Its totient is φ = 2013007272120.

The previous prime is 2013011101987. The next prime is 2013011102027. The reversal of 2013011102023 is 3202011103102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2013011102023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2013011101988 and 2013011102006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013011102027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 971661 + ... + 2229382.

It is an arithmetic number, because the mean of its divisors is an integer number (503253732982).

Almost surely, 2^{2013011102023} is an apocalyptic number.

2013011102023 is a deficient number, since it is larger than the sum of its proper divisors (3829905).

2013011102023 is an equidigital number, since it uses as much as digits as its factorization.

2013011102023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3829904.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 2013011102023 its reverse (3202011103102), we get a palindrome (5215022205125).

The spelling of 2013011102023 in words is "two trillion, thirteen billion, eleven million, one hundred two thousand, twenty-three".