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2013011130022 = 25821172909391
BaseRepresentation
bin11101010010110000110…
…100000011011010100110
321010102221012120201221121
4131102300310003122212
5230440121322130042
64140433050404154
7265302202166524
oct35226064033246
97112835521847
102013011130022
11706793338402
1228617543065a
13117a98032089
146d6048b5314
153756a3cc367
hex1d4b0d036a6

2013011130022 has 8 divisors (see below), whose sum is σ = 3020035440672. Its totient is φ = 1006332649800.

The previous prime is 2013011130007. The next prime is 2013011130023. The reversal of 2013011130022 is 2200311103102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 2013011129978 and 2013011130005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013011130023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86443054 + ... + 86466337.

It is an arithmetic number, because the mean of its divisors is an integer number (377504430084).

Almost surely, 22013011130022 is an apocalyptic number.

2013011130022 is a deficient number, since it is larger than the sum of its proper divisors (1007024310650).

2013011130022 is a wasteful number, since it uses less digits than its factorization.

2013011130022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 172915214.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 2013011130022 its reverse (2200311103102), we get a palindrome (4213322233124).

The spelling of 2013011130022 in words is "two trillion, thirteen billion, eleven million, one hundred thirty thousand, twenty-two".

Divisors: 1 2 5821 11642 172909391 345818782 1006505565011 2013011130022