Search a number
-
+
2013012112133 = 11474517861997
BaseRepresentation
bin11101010010110000110…
…111110011001100000101
321010102221021102122011002
4131102300313303030011
5230440122100042013
64140433123423045
7265302213430031
oct35226067631405
97112837378132
102013012112133
11706793949270
12286175824a85
13117a982b70c9
146d604a8d1c1
153756a523358
hex1d4b0df3305

2013012112133 has 16 divisors (see below), whose sum is σ = 2243236011264. Its totient is φ = 1790676010560.

The previous prime is 2013012112057. The next prime is 2013012112187. The reversal of 2013012112133 is 3312112103102.

It is a happy number.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013012112133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013012192133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1904291 + ... + 2766287.

It is an arithmetic number, because the mean of its divisors is an integer number (140202250704).

Almost surely, 22013012112133 is an apocalyptic number.

It is an amenable number.

2013012112133 is a deficient number, since it is larger than the sum of its proper divisors (230223899131).

2013012112133 is a wasteful number, since it uses less digits than its factorization.

2013012112133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 866572.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 2013012112133 its reverse (3312112103102), we get a palindrome (5325124215235).

The spelling of 2013012112133 in words is "two trillion, thirteen billion, twelve million, one hundred twelve thousand, one hundred thirty-three".

Divisors: 1 11 47 517 4517 49687 212299 861997 2335289 9481967 40513859 445652449 3893640449 42830044939 183001101103 2013012112133