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201301310 = 2572410819
BaseRepresentation
bin10111111111110…
…01110100111110
3112000210011111002
423333321310332
5403013120220
631550330302
74663014200
oct1377716476
9460704432
10201301310
11a36a1721
12574b9992
1332921702
141ca40770
1512a14c75
hexbff9d3e

201301310 has 24 divisors (see below), whose sum is σ = 421501320. Its totient is φ = 69017424.

The previous prime is 201301307. The next prime is 201301319. The reversal of 201301310 is 13103102.

It is a super-2 number, since 2×2013013102 = 81044434815432200, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201301291 and 201301300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201301319) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 204920 + ... + 205899.

It is an arithmetic number, because the mean of its divisors is an integer number (17562555).

Almost surely, 2201301310 is an apocalyptic number.

201301310 is an abundant number, since it is smaller than the sum of its proper divisors (220200010).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201301310 is a wasteful number, since it uses less digits than its factorization.

201301310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 410840 (or 410833 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 201301310 is about 14188.0692837327. The cubic root of 201301310 is about 586.0691578542.

Adding to 201301310 its reverse (13103102), we get a palindrome (214404412).

The spelling of 201301310 in words is "two hundred one million, three hundred one thousand, three hundred ten".

Divisors: 1 2 5 7 10 14 35 49 70 98 245 490 410819 821638 2054095 2875733 4108190 5751466 14378665 20130131 28757330 40260262 100650655 201301310