Base | Representation |
---|---|
bin | 10010101111110110… |
… | …010110110010100111 |
3 | 1220221220101121120112 |
4 | 102233312112302213 |
5 | 312211303143421 |
6 | 13125254323235 |
7 | 1311562201616 |
oct | 225766266247 |
9 | 56856347515 |
10 | 20130131111 |
11 | 859aa304a2 |
12 | 3a9965951b |
13 | 1b8a63acac |
14 | d8d6bb87d |
15 | 7cc3c345b |
hex | 4afd96ca7 |
20130131111 has 2 divisors, whose sum is σ = 20130131112. Its totient is φ = 20130131110.
The previous prime is 20130131041. The next prime is 20130131149. The reversal of 20130131111 is 11113103102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20130131111 - 210 = 20130130087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20130131011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065065555 + 10065065556.
It is an arithmetic number, because the mean of its divisors is an integer number (10065065556).
Almost surely, 220130131111 is an apocalyptic number.
20130131111 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130131111 is an equidigital number, since it uses as much as digits as its factorization.
20130131111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 20130131111 its reverse (11113103102), we get a palindrome (31243234213).
The spelling of 20130131111 in words is "twenty billion, one hundred thirty million, one hundred thirty-one thousand, one hundred eleven".
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