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2013013552157 is a prime number
BaseRepresentation
bin11101010010110000111…
…101010010110000011101
321010102221101010210111022
4131102300331102300131
5230440122432132112
64140433214333525
7265302231605246
oct35226075226035
97112841123438
102013013552157
11706794742173
122861761ba2a5
13117a9869c6aa
146d604d45ccd
153756a709d72
hex1d4b0f52c1d

2013013552157 has 2 divisors, whose sum is σ = 2013013552158. Its totient is φ = 2013013552156.

The previous prime is 2013013552117. The next prime is 2013013552169. The reversal of 2013013552157 is 7512553103102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1979027154841 + 33986397316 = 1406779^2 + 184354^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013013552157 - 232 = 2008718584861 is a prime.

It is a super-2 number, since 2×20130135521572 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013013552117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006506776078 + 1006506776079.

It is an arithmetic number, because the mean of its divisors is an integer number (1006506776079).

Almost surely, 22013013552157 is an apocalyptic number.

It is an amenable number.

2013013552157 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013013552157 is an equidigital number, since it uses as much as digits as its factorization.

2013013552157 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31500, while the sum is 35.

Adding to 2013013552157 its reverse (7512553103102), we get a palindrome (9525566655259).

The spelling of 2013013552157 in words is "two trillion, thirteen billion, thirteen million, five hundred fifty-two thousand, one hundred fifty-seven".