Base | Representation |
---|---|
bin | 11101010010110000111… |
… | …101010010101111110101 |
3 | 21010102221101010210102211 |
4 | 131102300331102233311 |
5 | 230440122432131432 |
6 | 4140433214333421 |
7 | 265302231605161 |
oct | 35226075225765 |
9 | 7112841123384 |
10 | 2013013552117 |
11 | 706794742137 |
12 | 2861761ba271 |
13 | 117a9869c679 |
14 | 6d604d45ca1 |
15 | 3756a709d47 |
hex | 1d4b0f52bf5 |
2013013552117 has 2 divisors, whose sum is σ = 2013013552118. Its totient is φ = 2013013552116.
The previous prime is 2013013552097. The next prime is 2013013552157. The reversal of 2013013552117 is 7112553103102.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2002072182916 + 10941369201 = 1414946^2 + 104601^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013013552117 is a prime.
It is a super-2 number, since 2×20130135521172 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013013552157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006506776058 + 1006506776059.
It is an arithmetic number, because the mean of its divisors is an integer number (1006506776059).
Almost surely, 22013013552117 is an apocalyptic number.
It is an amenable number.
2013013552117 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013013552117 is an equidigital number, since it uses as much as digits as its factorization.
2013013552117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6300, while the sum is 31.
Adding to 2013013552117 its reverse (7112553103102), we get a palindrome (9125566655219).
The spelling of 2013013552117 in words is "two trillion, thirteen billion, thirteen million, five hundred fifty-two thousand, one hundred seventeen".
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