20130140343431 has 4 divisors (see below), whose sum is σ = 20132988015000. Its totient is φ = 20127292671864.

The previous prime is 20130140343421. The next prime is 20130140343451. The reversal of 20130140343431 is 13434304103102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-20130140343431 is a prime.

It is a super-2 number, since 2×20130140343431² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20130140343394 and 20130140343403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20130140343421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1423825181 + ... + 1423839318.

It is an arithmetic number, because the mean of its divisors is an integer number (5033247003750).

Almost surely, 2^{20130140343431} is an apocalyptic number.

20130140343431 is a deficient number, since it is larger than the sum of its proper divisors (2847671569).

20130140343431 is an equidigital number, since it uses as much as digits as its factorization.

20130140343431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2847671568.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 20130140343431 its reverse (13434304103102), we get a palindrome (33564444446533).

The spelling of 20130140343431 in words is "twenty trillion, one hundred thirty billion, one hundred forty million, three hundred forty-three thousand, four hundred thirty-one".