20130141024031 has 2 divisors, whose sum is σ = 20130141024032. Its totient is φ = 20130141024030.

The previous prime is 20130141024023. The next prime is 20130141024053. The reversal of 20130141024031 is 13042014103102.

It is an a-pointer prime, because the next prime (20130141024053) can be obtained adding 20130141024031 to its sum of digits (22).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20130141024031 - 2³ = 20130141024023 is a prime.

It is a super-2 number, since 2×20130141024031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20130141023993 and 20130141024011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20130141024011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065070512015 + 10065070512016.

It is an arithmetic number, because the mean of its divisors is an integer number (10065070512016).

Almost surely, 2^{20130141024031} is an apocalyptic number.

20130141024031 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130141024031 is an equidigital number, since it uses as much as digits as its factorization.

20130141024031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 20130141024031 its reverse (13042014103102), we get a palindrome (33172155127133).

The spelling of 20130141024031 in words is "twenty trillion, one hundred thirty billion, one hundred forty-one million, twenty-four thousand, thirty-one".