2013014113421 has 2 divisors, whose sum is σ = 2013014113422. Its totient is φ = 2013014113420.

The previous prime is 2013014113403. The next prime is 2013014113441. The reversal of 2013014113421 is 1243114103102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1588131764521 + 424882348900 = 1260211^2 + 651830^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013014113421 - 2²² = 2013009919117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013014113441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006507056710 + 1006507056711.

It is an arithmetic number, because the mean of its divisors is an integer number (1006507056711).

Almost surely, 2^{2013014113421} is an apocalyptic number.

It is an amenable number.

2013014113421 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013014113421 is an equidigital number, since it uses as much as digits as its factorization.

2013014113421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 2013014113421 its reverse (1243114103102), we get a palindrome (3256128216523).

The spelling of 2013014113421 in words is "two trillion, thirteen billion, fourteen million, one hundred thirteen thousand, four hundred twenty-one".