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20130212103 = 341163660261
BaseRepresentation
bin10010101111110110…
…101010100100000111
31220221220112201200020
4102233312222210013
5312211313241403
613125300150223
71311562660011
oct225766524407
956856481606
1020130212103
11859aa86331
123a99698373
131b8a668b11
14d8d6dd1b1
157cc3dc453
hex4afdaa907

20130212103 has 8 divisors (see below), whose sum is σ = 27494924016. Its totient is φ = 13092820800.

The previous prime is 20130212101. The next prime is 20130212129. The reversal of 20130212103 is 30121203102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 20130212103 - 21 = 20130212101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20130212101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 81830008 + ... + 81830253.

It is an arithmetic number, because the mean of its divisors is an integer number (3436865502).

Almost surely, 220130212103 is an apocalyptic number.

20130212103 is a deficient number, since it is larger than the sum of its proper divisors (7364711913).

20130212103 is a wasteful number, since it uses less digits than its factorization.

20130212103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163660305.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 20130212103 its reverse (30121203102), we get a palindrome (50251415205).

Subtracting 20130212103 from its reverse (30121203102), we obtain a palindrome (9990990999).

The spelling of 20130212103 in words is "twenty billion, one hundred thirty million, two hundred twelve thousand, one hundred three".

Divisors: 1 3 41 123 163660261 490980783 6710070701 20130212103