Search a number
-
+
20130213001200 = 24352194379259907
BaseRepresentation
bin1001001001110111011100…
…01100011111011111110000
32122021102121011012022222220
410210323232030133133300
510114303134012014300
6110451405302401040
74145234305202661
oct444735614373760
978242534168886
1020130213001200
1164611a249a115
122311453730180
13b3036a345483
144d8443b31368
1524d976770da0
hex124eee31f7f0

20130213001200 has 480 divisors, whose sum is σ = 70335679180800. Its totient is φ = 4904363842560.

The previous prime is 20130213001169. The next prime is 20130213001273. The reversal of 20130213001200 is 210031203102.

It is a super-2 number, since 2×201302130012002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 20130213001200.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 77321647 + ... + 77581553.

It is an arithmetic number, because the mean of its divisors is an integer number (146532664960).

Almost surely, 220130213001200 is an apocalyptic number.

20130213001200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20130213001200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (35167839590400).

20130213001200 is an abundant number, since it is smaller than the sum of its proper divisors (50205466179600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20130213001200 is a wasteful number, since it uses less digits than its factorization.

20130213001200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 260069 (or 260058 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 20130213001200 its reverse (210031203102), we get a palindrome (20340244204302).

The spelling of 20130213001200 in words is "twenty trillion, one hundred thirty billion, two hundred thirteen million, one thousand, two hundred".