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201303102022 = 21119347410057
BaseRepresentation
bin1011101101111010011…
…0011001001001000110
3201020121011022010102021
42323132212121021012
511244232043231042
6232251040033354
720354323064161
oct2733646311106
9636534263367
10201303102022
1178410398020
123302000285a
1315ca12a2069
149a591acad8
155382a78867
hex2ede999246

201303102022 has 16 divisors (see below), whose sum is σ = 331111845072. Its totient is φ = 91027307520.

The previous prime is 201303102017. The next prime is 201303102029. The reversal of 201303102022 is 220201303102.

It is a super-3 number, since 3×2013031020223 (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201303101987 and 201303102005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201303102029) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23700783 + ... + 23709274.

It is an arithmetic number, because the mean of its divisors is an integer number (20694490317).

Almost surely, 2201303102022 is an apocalyptic number.

201303102022 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

201303102022 is a deficient number, since it is larger than the sum of its proper divisors (129808743050).

201303102022 is a wasteful number, since it uses less digits than its factorization.

201303102022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47410263.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 201303102022 its reverse (220201303102), we get a palindrome (421504405124).

The spelling of 201303102022 in words is "two hundred one billion, three hundred three million, one hundred two thousand, twenty-two".

Divisors: 1 2 11 22 193 386 2123 4246 47410057 94820114 521510627 1043021254 9150141001 18300282002 100651551011 201303102022