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2013033021341 is a prime number
BaseRepresentation
bin11101010010110010000…
…111100011111110011101
321010102222201202221012012
4131102302013203332131
5230440142423140331
64140435151521005
7265302556233566
oct35226207437635
97112881687165
102013033021341
117067a472a701
12286180829165
13117a9c728314
146d60777316d
153756c2a382b
hex1d4b21e3f9d

2013033021341 has 2 divisors, whose sum is σ = 2013033021342. Its totient is φ = 2013033021340.

The previous prime is 2013033021289. The next prime is 2013033021347. The reversal of 2013033021341 is 1431203303102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1711769255716 + 301263765625 = 1308346^2 + 548875^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013033021341 - 218 = 2013032759197 is a prime.

It is a super-2 number, since 2×20130330213412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013033021347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006516510670 + 1006516510671.

It is an arithmetic number, because the mean of its divisors is an integer number (1006516510671).

Almost surely, 22013033021341 is an apocalyptic number.

It is an amenable number.

2013033021341 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013033021341 is an equidigital number, since it uses as much as digits as its factorization.

2013033021341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 2013033021341 its reverse (1431203303102), we get a palindrome (3444236324443).

The spelling of 2013033021341 in words is "two trillion, thirteen billion, thirty-three million, twenty-one thousand, three hundred forty-one".