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201304121111100 = 22345276135791741
BaseRepresentation
bin101101110001010111000100…
…101000010111001000111100
3222101202111010022120122110000
4231301113010220113020330
5202341131320001023400
61552045500410514300
760254512532002320
oct5561270450271074
9871674108518400
10201304121111100
115916166441a287
121a6b2106a35990
138842b881005a7
14379d25864b980
1518415aebae600
hexb715c4a1723c

201304121111100 has 360 divisors, whose sum is σ = 746986356736928. Its totient is φ = 45937301644800.

The previous prime is 201304121111089. The next prime is 201304121111201. The reversal of 201304121111100 is 1111121403102.

201304121111100 is a `hidden beast` number, since 2 + 0 + 1 + 30 + 412 + 111 + 110 + 0 = 666.

201304121111100 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 31861230 + ... + 37652970.

Almost surely, 2201304121111100 is an apocalyptic number.

201304121111100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201304121111100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (373493178368464).

201304121111100 is an abundant number, since it is smaller than the sum of its proper divisors (545682235625828).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201304121111100 is a wasteful number, since it uses less digits than its factorization.

201304121111100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5792387 (or 5792371 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 18.

Adding to 201304121111100 its reverse (1111121403102), we get a palindrome (202415242514202).

The spelling of 201304121111100 in words is "two hundred one trillion, three hundred four billion, one hundred twenty-one million, one hundred eleven thousand, one hundred".