Base | Representation |
---|---|
bin | 1011101101111010101… |
… | …0010110101000110101 |
3 | 201020121020020212201112 |
4 | 2323132222112220311 |
5 | 11244232324442331 |
6 | 232251114204405 |
7 | 20354334650303 |
oct | 2733652265065 |
9 | 636536225645 |
10 | 201304140341 |
11 | 78410a37137 |
12 | 33020423705 |
13 | 15ca1576855 |
14 | 9a5939d273 |
15 | 5382bd132b |
hex | 2edea96a35 |
201304140341 has 2 divisors, whose sum is σ = 201304140342. Its totient is φ = 201304140340.
The previous prime is 201304140293. The next prime is 201304140347. The reversal of 201304140341 is 143041403102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 196179012241 + 5125128100 = 442921^2 + 71590^2 .
It is a cyclic number.
It is not a de Polignac number, because 201304140341 - 210 = 201304139317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201304140347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100652070170 + 100652070171.
It is an arithmetic number, because the mean of its divisors is an integer number (100652070171).
Almost surely, 2201304140341 is an apocalyptic number.
It is an amenable number.
201304140341 is a deficient number, since it is larger than the sum of its proper divisors (1).
201304140341 is an equidigital number, since it uses as much as digits as its factorization.
201304140341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 201304140341 its reverse (143041403102), we get a palindrome (344345543443).
The spelling of 201304140341 in words is "two hundred one billion, three hundred four million, one hundred forty thousand, three hundred forty-one".
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