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20131012000110 = 235112943155931379
BaseRepresentation
bin1001001001111000111011…
…10100011011100101101110
32122021111122211122200110010
410210330131310123211232
510114311303033000420
6110452020443554050
74145263146446604
oct444743564334556
978244584580403
1020131012000110
1164615725068a0
12231163722b926
13b30466a377ab
144d84bbcb9874
1524d9c199b4e0
hex124f1dd1b96e

20131012000110 has 256 divisors, whose sum is σ = 55829689344000. Its totient is φ = 4599281809920.

The previous prime is 20131012000031. The next prime is 20131012000147. The reversal of 20131012000110 is 1100021013102.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 641528401 + ... + 641559779.

It is an arithmetic number, because the mean of its divisors is an integer number (218084724000).

Almost surely, 220131012000110 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20131012000110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27914844672000).

20131012000110 is an abundant number, since it is smaller than the sum of its proper divisors (35698677343890).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20131012000110 is a wasteful number, since it uses less digits than its factorization.

20131012000110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33031.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 20131012000110 its reverse (1100021013102), we get a palindrome (21231033013212).

The spelling of 20131012000110 in words is "twenty trillion, one hundred thirty-one billion, twelve million, one hundred ten", and thus it is an aban number.