201310300111 has 4 divisors (see below), whose sum is σ = 201313442592. Its totient is φ = 201307157632.

The previous prime is 201310300091. The next prime is 201310300159. The reversal of 201310300111 is 111003013102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-201310300111 is a prime.

It is a super-2 number, since 2×201310300111² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201310300091 and 201310300100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201310370111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1473106 + ... + 1603951.

It is an arithmetic number, because the mean of its divisors is an integer number (50328360648).

Almost surely, 2^201310300111 is an apocalyptic number.

201310300111 is a deficient number, since it is larger than the sum of its proper divisors (3142481).

201310300111 is an equidigital number, since it uses as much as digits as its factorization.

201310300111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3142480.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 201310300111 its reverse (111003013102), we get a palindrome (312313313213).

The spelling of 201310300111 in words is "two hundred one billion, three hundred ten million, three hundred thousand, one hundred eleven".