Base | Representation |
---|---|
bin | 101101110001011101100110… |
… | …011001001100010111011111 |
3 | 222101210011012210001122202000 |
4 | 231301131212121030113133 |
5 | 202341240143240323403 |
6 | 1552053020103533343 |
7 | 60255151316450160 |
oct | 5561354631142737 |
9 | 871704183048660 |
10 | 201311130011103 |
11 | 591646307a2622 |
12 | 1a6b354215a253 |
13 | 88437342014b8 |
14 | 379d721443767 |
15 | 18418701857a3 |
hex | b7176664c5df |
201311130011103 has 64 divisors (see below), whose sum is σ = 357090549104640. Its totient is φ = 109662572844000.
The previous prime is 201311130011093. The next prime is 201311130011111. The reversal of 201311130011103 is 301110031113102.
201311130011103 is a `hidden beast` number, since 201 + 311 + 130 + 0 + 11 + 10 + 3 = 666.
It is not a de Polignac number, because 201311130011103 - 26 = 201311130011039 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201311130011153) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 256020123 + ... + 256805228.
It is an arithmetic number, because the mean of its divisors is an integer number (5579539829760).
Almost surely, 2201311130011103 is an apocalyptic number.
201311130011103 is a deficient number, since it is larger than the sum of its proper divisors (155779419093537).
201311130011103 is a wasteful number, since it uses less digits than its factorization.
201311130011103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 512825465 (or 512825459 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 201311130011103 its reverse (301110031113102), we get a palindrome (502421161124205).
The spelling of 201311130011103 in words is "two hundred one trillion, three hundred eleven billion, one hundred thirty million, eleven thousand, one hundred three".
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