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201311221300200 = 2332521120834881053
BaseRepresentation
bin101101110001011101101011…
…110101011011101111101000
3222101210011110010211121211200
4231301131223311123233220
5202341240340123101300
61552053033124324200
760255153505422144
oct5561355365335750
9871704403747750
10201311221300200
1159164678284460
121a6b3568843660
13884374a0b510b
14379d72d608224
1518418781b9200
hexb7176bd5bbe8

201311221300200 has 288 divisors, whose sum is σ = 737885333521440. Its totient is φ = 48779281267200.

The previous prime is 201311221300193. The next prime is 201311221300223. The reversal of 201311221300200 is 2003122113102.

201311221300200 is a `hidden beast` number, since 2 + 0 + 1 + 311 + 22 + 130 + 0 + 200 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 38802874 + ... + 43683926.

It is an arithmetic number, because the mean of its divisors is an integer number (2562101852505).

Almost surely, 2201311221300200 is an apocalyptic number.

201311221300200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201311221300200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (368942666760720).

201311221300200 is an abundant number, since it is smaller than the sum of its proper divisors (536574112221240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201311221300200 is a wasteful number, since it uses less digits than its factorization.

201311221300200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4883169 (or 4883157 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 201311221300200 its reverse (2003122113102), we get a palindrome (203314343413302).

The spelling of 201311221300200 in words is "two hundred one trillion, three hundred eleven billion, two hundred twenty-one million, three hundred thousand, two hundred".